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这样肯定要超时,有没有好方法呢??求助

Posted by cpp050300448067 at 2005-04-25 18:40:00 on Problem 1650
#include <iostream.h>
inline double dabs(double t)
{ if(t>=0) return t;
	else return -t;
}
void main()
{
	double A;
	double d,n;
	int N,D;
	double exa;
	long L;
	cin >> A;
	int Ai = (int)A;
	cin >> L;
	exa = A - Ai;
	for( d=1;d <= L;d++)
		for(n=Ai * d ; n <= L;n++)
		  if(dabs(n/d - A)<exa)
			{N = n;
			 D = d;
			 exa = dabs(n/d - A);}
	cout << N << ' ' << D <<endl;
}

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