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则么会过不去?var p,e,i,d,t,total,j,g,h,x:longint; a,b,k:array[1..3] of int64; ji:int64; begin read(p,e,i,d); {if (p=2)and(i-2)and(} t:=23*28*33; g:=1; a[1]:=p mod 23;a[2]:=e mod 28;a[3]:=i mod 33; b[1]:=23; b[2]:=28;;b[3]:=33; g:=1; while (p<>-1)and(i<>-1)and(e<>-1)and(d<>-1) do begin total:=0; for j:=1 to 3 do begin h:=t div b[j]; k[j]:=h; while (k[j] mod b[j]<>a[j]) do k[j]:=k[j]+h; end; for j:=1 to 3do total:=total+k[j]; while (total>t)and(total>d) do total:=total-t; ji:=total-d; if ji<=0 then ji:=21252+ji; writeln('Case ',g,': the next triple peak occurs in ',ji,' days'); g:=g+1; read(p,e,i,d); a[1]:=p mod 23;a[2]:=e mod 28;a[3]:=i mod 33; end; end. Followed by: Post your reply here: |
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