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Re:递归AC,其实图形是对称的,每次只考虑前1/3就OK了(附代码)In Reply To:递归AC,其实图形是对称的,每次只考虑前1/3就OK了(附代码) Posted by:zjc0823 at 2010-05-07 10:43:33 > #include <iostream>
> using namespace std;
>
> int f(int n) //3的n次幂
> {
> int s=1,i;
> for(i=0;i<n;i++)
> s*=3;
> return s;
> }
>
> void cantor(int n) //递归
> {
> int i,x;
> if(n==0)
> {
> cout<<"-";
> }
> else
> {
> x=f(n-1);
> cantor(n-1);
> for(i=0;i<x;i++)
> {
> cout<<" ";
> }
> cantor(n-1);
> }
> }
>
> int main()
> {
> int n,m;
> while(cin>>n)
> {
> cantor(n);
> cout<<endl;
> }
> return 0;
> }
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