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Re:跪求大牛们帮我看下我这个程序出错在哪里?数据在本地都通的过,一上去就wa.

Posted by xugen at 2010-11-21 15:15:52 on Problem 1013
In Reply To:跪求大牛们帮我看下我这个程序出错在哪里?数据在本地都通的过,一上去就wa. Posted by:xugen at 2010-11-21 15:15:00
> #include<iostream>
> #include<string>
> //#include<cstring>
> #include<memory.h>
> using namespace std;
> char weigh[6][7];
> string word[3];
> int signal[12]; 
> 
> int main()
> {
> 	int j,length,n,k;
> 	cin>>n;
>     while(n--)
> 	{
> 		
> 		memset(weigh,0,42);
> 		for(j=0;j<12;j++)
> 			signal[j]=3;
> 		for(j=0;j<5;j+=2)
> 			cin>>weigh[j]>>weigh[j+1]>>word[j/2];
> 		for(j=0;j<5;j+=2)
> 		{
> 			length=strlen(weigh[j]);
> 			if(word[j/2]=="even")
> 				for(k=0;k<length;k++)
> 					signal[weigh[j][k]-'A']=signal[weigh[j+1][k]-'A']=0;
> 			else if(word[j/2]=="up")
> 			{
> 				for(k=0;k<length;k++)
> 				{
> 					if((signal[weigh[j][k]-'A']==2)||(signal[weigh[j][k]-'A']==3))
> 					{
> 						signal[weigh[j][k]-'A']=2;
> 					}
> 					else
> 					{
> 						signal[weigh[j][k]-'A']=0;
> 					}
> 					if((signal[weigh[j+1][k]-'A']==1)||(signal[weigh[j+1][k]-'A']==3))
> 					{
> 						signal[weigh[j+1][k]-'A']=1;
> 					}
> 					else
> 					{
> 						signal[weigh[j+1][k]-'A']=0;
> 					}
> 				}
> 			}
> 			else if(word[j/2]=="down")
> 			{
> 				for(k=0;k<length;k++)
> 				{
> 					if((signal[weigh[j][k]-'A']==1)||(signal[weigh[j][k]-'A']==3))
> 					{
> 						signal[weigh[j][k]-'A']=1;
> 					}
> 					else
> 					{
> 						signal[weigh[j][k]-'A']=0;
> 					}
> 					if((signal[weigh[j+1][k]-'A']==2)||(signal[weigh[j+1][k]-'A']==3))
> 					{
> 						signal[weigh[j+1][k]-'A']=2;
> 					}
> 					else
> 					{
> 						signal[weigh[j+1][k]-'A']=0;
> 					}
> 				}
> 			}
> 			else ;
> 		}
> 			for(k=0;k<12;k++)
> 			{
> 		
> 				if(signal[k]==1)
> 				{
> 				
> 					cout<<char('A'+k)<<" is the counterfeit coin and it is light."<<endl;
> 					break;
> 				}
> 				else if (signal[k]==2)
> 				{
> 					
> 					cout<<char('A'+k)<<" is the counterfeit coin and it is heavy."<<endl;
> 					break;
> 				}
> 				
> 			}		
> 	}
> 	return 0;
> }

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