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感觉挺容易懂的,,,仅供参考....#include <iostream>
using namespace std;
#define max(a,b) ((a>b)?(a):(b))
int a[50001];//数据数组
int dpy[50001];//前i个数的1个子串的最大值,,必包含第i个..
int dpn[50001];//前i个数的1个子串的最大值,,不必包含第i个..
int dp2[50001];//前i个数的2个子串的最大值,必包含第i个...
int main()
{
int t;
for(scanf("%d",&t);t--;)
{
int n;
scanf("%d",&n);
int i;
for(i=1;i<=n;i++)
scanf("%d",&a[i]);
dpy[0]=dpn[0]=-1000000;
for(i=1;i<=n;i++)
{
dpy[i]=max(dpy[i-1]+a[i],a[i]);
dpn[i]=max(dpy[i],dpn[i-1]);
}
int ans=INT_MIN;
dp2[1]=a[1];
for(i=2;i<=n;i++)
{
dp2[i]=max(dpn[i-1]+a[i],dp2[i-1]+a[i]);
ans=max(dp2[i],ans);
}
printf("%d\n",ans);
}
return 0;
}
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