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弱弱地问，二元函数的最值怎么个求法

Posted by c0500448129 at 2005-04-24 13:50:15 on Problem 2420
In Reply To:被蒙了，以为是平均值，newton iteration不错 Posted by:frkstyc at 2005-04-24 13:07:19

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还是牛迭，不过导数变成偏导数，小心平均值落在一个点上，这时跑偏一些就可以了 (0) frkstyc 2005-04-24 13:52:55
- 是求两个偏导为零的点 (0) frkstyc 2005-04-24 13:54:12
  - 是不是解f'(x)=0 and f'(y)=0两个方程，还有解的时候两个方程是不是独立的？ (0) c0500448129 2005-04-24 14:01:52
    - 就是这样，然后选好的初值让它迭代到最小的极小值；两个要同时算 (0) frkstyc 2005-04-24 14:05:20
      - 非常感谢！ (13) c0500448129 2005-04-24 14:12:12
    - 联立求解啊，x方向上的偏导和y方向上的偏导都为0 (0) TN 2005-04-24 14:05:44

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