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这都能过.....#include<stdio.h> int a[1000001]; int b[10001]; int main() { int i,j,k,n,mid; while (scanf("%d",&n)!=EOF) { for (i=0;i<=1000000;i++) a[i]=0; for (i=1;i<=n;i++) { scanf("%d",&k); a[k]++; } j=0; for (i=1;i<=1000000;i++) while (a[i]>0) { j++; b[j]=i; a[i]--; } if (n%2==1) printf("%d\n",b[(n+1)/2]); else printf("%d",(b[n/2]+b[n/2+1])/2); } return 0; } Followed by: Post your reply here: |
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