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贴下本人代码。。。

Posted by pengshihui at 2010-10-12 20:29:44 on Problem 1835
#include "stdio.h"
#include "memory.h"
int temp[6];
int direct[5][6]={{1,0,3,2,4,5},{2,3,1,0,4,5},{3,2,0,1,4,5},{4,5,2,3,1,0},{5,4,2,3,0,1}};
int d[6][3]={{1,0,0},{0,1,0},{0,0,1},{-1,0,0},{0,-1,0},{0,0,-1}};
int code(char * s){
	switch(s[0]){
		case 'l': return 1;
		case 'r': return 2;
		case 'u': return 3;
		case 'd': return 4;
		case 'b': return 0;
		default : return 5;
	}
}
int main(void){
	char str[20];
	int m,n,t,result1[6]={0,3,4,1,2,5},x,y,z,l,i,j,result[6];
	scanf("%d",&m);
	while(m--){
		scanf("%d",&n);
		x=y=z=0;
		memcpy(result,result1,sizeof(result));
		while(n--){
			scanf("%s%d",str,&t);
			l=code(str);
			if(l!=5){
				for(i=0;i!=6;++i) temp[i]=result[direct[l][i]];
				memcpy(result,temp,sizeof(temp));
			}
			x+=d[result[0]][0]*t,y+=d[result[0]][1]*t,z+=d[result[0]][2]*t;
		}
		printf("%d %d %d %d\n",x,y,z,result[0]);
	}
	return 0;
}

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