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C++标程------------------0MS#include <stdio.h>
int t,p,n,ans,k=0;
int main(void){
while (scanf ("%d%d",&p,&n)!=EOF&&n){
ans=1;
while (n>0)ans=(ans*(n%p+1))%10000,n/=p;
printf ("Case %d: %04d\n",++k,ans);
}
return 0;
}
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