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其实这样就可以了。#include<iostream> using namespace std; const int s[10]={1,1,2,6,24,120,720,5040,40320,362880}; int main() { int n; while(scanf("%d",&n)!=EOF) { if(n<0) break; else if(n==0) { printf("NO\n"); } else { for(int i=9;i>=0;i--) { if(n>=s[i]) n=n-s[i]; } if(n==0) printf("YES\n"); else printf("NO\n"); } } return 0; } Followed by: Post your reply here: |
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