 |
| ||||
Home Page
F.A.Qs
Statistical Charts
Past Contests
Scheduled Contests
Award Contest
| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
一开始还以为是搜索……后来发现其实只要验证一下就好了……规则是如果总数是奇数就输出yes，如果总数是偶数就统计一下奇数位置的1的个数和偶数位置的1的个数，如果两者相差小于等于1就输出yes，不然输出NO…… 原理大概就是对于偶数的情况，每一次交换都不会改变那个差值，而对于奇数，shift之后就能够实现奇偶的互换 Followed by:
Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator
