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Re:高精度除法+高精度加法In Reply To:高精度除法+高精度加法 Posted by:Magic347 at 2010-06-24 12:50:58 直接算就行了 #include<iostream> #include<algorithm> #include<map> #include<stdio.h> using namespace std; int main() { int a[11]; a[0]=1; for(int i=1;i<10;i++)a[i]=i*a[i-1]; //cout<<a[9]; double b[11]={0}; cout<<"n e"<<endl<<"- -----------"<<endl; for(int i=0;i<10;i++){b[i]=1000000000.0/a[i]+b[i-1];} cout<<"0 1"<<endl<<"1 2"<<endl<<"2 2.5"<<endl; for(int i=3;i<10;i++){ printf("%d %.9lf\n",i,b[i]/1000000000.0); } } Followed by: Post your reply here: |
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