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精度够吗?In Reply To:这道题,偶用解析几何过的,求两条直线垂直平分线的交点,即为圆心,然后求半径.看了大家的帖子,学习!!!!!! Posted by:Ontheline at 2009-02-18 12:18:43 我用这个办法发现精度远远不够啊 我的代码,精度不够 #include<iostream> #include<cmath> using namespace std; const long double PI=3.141592653589793; int main() { double x1,x2,x3,y1,y2,y3; while(scanf("%lf%lf%lf%lf%lf%lf",&x1,&y1,&x2,&y2,&x3,&y3)!=EOF) { long double k1=-(x2-x1)/(y2-y1); long double k2=-(x3-x2)/(y3-y2); long double p1x=(x1+x2)/2,p1y=(y1+y2)/2,p2x=(x2+x3)/2,p2y=(y2+y3)/2; long double b1=p1y-k1*p1x,b2=p2y-k2*p2x; long double x=(b1-b2)/(k1-k2),y=k1*x+b1; long double r=sqrt((x1-x)*(x1-x)+(y1-y)*(y1-y)); long double ans=PI*2.0*r; printf("%.2lf\n",ans); } return 0; } Followed by: Post your reply here: |
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