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貌似题目有点问题,还是我理解错了题目说是所有的点都能到达A点,那么A点是sink,所以当有且仅有一个出度为0的联通分量的所有点才是解. 但是我这样写错了,后来改成了所有出度为0的联通分量的点,对了.......不理解中.....求高手解释 Followed by:
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