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一种非主流的解决方法、、0ms,很简单,和大家分享一下下#include <iostream> using namespace std; int main() { int a[1001],b[1001],i,j,k,n; cin>>n; for(i=1;i<=n;i++) cin>>a[i]; k=1; b[1]=a[1]; for(i=2;i<=n;i++){ if(a[i]>b[k]) b[++k]=a[i]; else{ j=k; while(a[i]<=b[j]) j--; b[j+1]=a[i]; } } cout<<k<<endl; } Followed by:
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