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一种非主流的解决方法、、0ms,很简单,和大家分享一下下#include <iostream>
using namespace std;
int main()
{
int a[1001],b[1001],i,j,k,n;
cin>>n;
for(i=1;i<=n;i++)
cin>>a[i];
k=1;
b[1]=a[1];
for(i=2;i<=n;i++){
if(a[i]>b[k]) b[++k]=a[i];
else{
j=k;
while(a[i]<=b[j]) j--;
b[j+1]=a[i];
}
}
cout<<k<<endl;
}
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