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Re:大开方便之门,这题解法In Reply To:大开方便之门,这题解法 Posted by:Base at 2008-11-20 13:55:31 最后一步“所以”我说清楚点 也就是来个积分 f[k]=1/(1-t)*max(2^(n-k),p*f(k-1)) 中的p对于t到1之间的值积分 简单的分一个段就行了 Followed by:
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