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23ms 的一个 C++ possible version#include <iostream>
using namespace std;
int main()
{
int p, e, i, d, cnt = 1;
while(cin >> p >> e >> i >> d, p != -1)
{
p %= 23;
e %= 28;
i %= 33;
int t = 0, s;
while(s = i + 33 * t,
! (s > d && (s - p) % 23 == 0 && (s - e) % 28 == 0 ) )
{
++t;
}
cout << "Case " << cnt++ << ": the next triple peak occurs in " << s - d << " days." << endl;
}
return 0;
}
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