> 我是这样想的：凡是超过2的我都将它%2，最后只剩下诸如1 0 1 0 0 0之类的，然后求和，我只要和数为偶的这些能divided都一一枚举出来即可.可是这样却WA，郁闷啊啊~~
> #include<iostream>
> using namespace std;
> void main()
> {
> 	int A[6],i,sum,onenum;
> 	int static num=0;
> 	while(1)
> 	{
> 		sum=0;onenum=0;
> 		for(i=0;i<6;i++)
> 		{
> 			cin>>A[i];
> 		}
> 		if(A[0]==0&&A[1]==0&&A[2]==0&&A[3]==0&&A[4]==0&&A[5]==0)
> 		{break;}
>         for(i=0;i<6;i++)
> 		{
> 			A[i]=(A[i]%2);
> 			if(A[i]==1){onenum++;}
> 			sum=(A[i]*(i+1))+sum;
> 		}
> 		if(sum%2==0)
> 		{
> 			if(onenum==0)
> 			{   
> 				cout<<"Collection #"<<++num<<":"<<endl;
> 				cout<<"Can be divided.";
> 			}
> 			else if(onenum==3)
> 			{
> 				if(A[0]==0&&A[2]==0&&A[4]==0)
> 				{cout<<"Collection #"<<++num<<":"<<endl;
> 				cout<<"Can be divided.";
> 				}
> 			   else
> 				for(i=0;i<6;i++)
> 				{
> 					if(A[i]*(i+1)==(sum/2))
> 					{
> 					 cout<<"Collection #"<<++num<<":"<<endl;
> 				     cout<<"Can be divided.";
> 					 break;
> 					}
> 				}
> 			}
> 	
> 	      else if(onenum==4)
> 		  {
> 			  if(A[0]==0&&A[4]==0&&A[3]==0&&A[5]==0)
> 			  {cout<<"Collection #"<<++num<<":"<<endl;
> 				     cout<<"Can't be divided.";
> 			  }
> 			  else
> 			  {
> 				  cout<<"Collection #"<<++num<<":"<<endl;
> 				  cout<<"Can be divided.";
> 			  }
> 		  }
>           else if(onenum==5)
> 		  {
>                  cout<<"Collection #"<<++num<<":"<<endl;
> 				 cout<<"Can be divided.";
> 		  }
> 		  else
> 		  { 
> 		          cout<<"Collection #"<<++num<<":"<<endl;
> 	              cout<<"Can't be divided.";
> 		  }
> 		}
> 	    else
> 		{ 
> 		cout<<"Collection #"<<++num<<":"<<endl;
> 	    cout<<"Can't be divided.";
> 		}
> 	    cout<<endl;
> 	}
> 	
> }
> 
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