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其实不用那么复杂的,老友,将最后一个月看成0月就好简单喇In Reply To:请教!老是woring answer!是什么问题啊。 Posted by:plumage at 2005-04-17 21:33:20 > #include<iostream.h>
> #include<string.h>
> #include<fstream.h>
>
> #define lofhaab 365
> #define loftzol 260
> char Tzolkin[21][10]={"","imix","ik","akbal","kan","chicchan","cimi","manik","lamat","muluk","ok","chuen","eb","ben","ix","mem","cib","caban","eznab","canac","ahau"};
> char Haab[20][10]={"","pop", "no", "zip", "zotz","tzec", "xul", "yoxkin", "mol", "chen", "yax", "zac", "ceh", "mac", "kankin", "muan", "pax", "koyab", "cumhu"};
> void main()
> {
> fstream fin("in.txt",ios::in||ios::out);
> int n;
>
> fin>>n;
> cout<<n<<endl;
> unsigned long day,year,days,name;
> char month[10];
> char point;
> int i,j;
> for(i=0;i<n;i++)
> {
> fin>>day>>point>>month>>year;
> for(j=1;j<20;j++)
> {
> if(strcmp(month,Haab[j])==0)
> break;
> }
>
> days=year*lofhaab+(day+1)+((j-1)*20);
>
> year=days/loftzol;//years in tozolkin
> days=days%loftzol;
>
> if(days==0)
> {
> days=loftzol;
> year--;
> }
> name=days%20;
> day=days%13;
>
> if(day==0)
> {
> day=13;
> }
> if(name==0)
> {
> name=20;
> }
>
> cout<<day<<" "<<Tzolkin[name]<<" "<<year<<endl;
> }
> }
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