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Re:暴力方法,一个一个排除,0MS过了,大牛见笑In Reply To:暴力方法,一个一个排除,0MS过了,大牛见笑 Posted by:bhq at 2009-07-31 15:16:30 > //如果某数有generator,它一定可以拆成:i*1001 + j*101 + k*11 + m*2 0<=i,j,k,m<=9
> //数组开到9*1001+9*101+9*11+9*2+1=10036
>
> #include <iostream>
> using namespace std;
>
> int main()
> {
> int selfnum[10036] = {0};
> for ( int i = 0 ; i < 10 ; ++ i )
> for ( int j = 0 ; j < 10 ; ++ j )
> for ( int k = 0 ; k < 10 ; ++ k )
> for ( int m = 0 ; m < 10 ; ++ m )
> selfnum[ i*1001 + j*101 + k*11 + m*2 ] = 1;
> for ( int i = 1 ; i <= 10000 ; ++ i )
> if ( selfnum[i] == 0 )
> cout << i << endl;
> return 0;
> }
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