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50题,小小的纪念下,代码留下,纯粹的二分匹配匈牙利算法模板题/*1274 Accepted 424K 16MS G++ 946B 2010-07-29 15:33:19 */
#include<stdio.h>
#include<string.h>
#define arr 201
int N,M,pre[arr];
bool map[arr][arr],used[arr];
bool find(int x)
{
int i;
for(i=1;i<=M;i++)
{
if(!used[i]&&map[x][i])
{
used[i]=1;
if(pre[i]==-1||find(pre[i]))
{
pre[i]=x;
return 1;
}
}
}
return 0;
}
int MMG()
{
int i,count=0;
memset(pre,-1,sizeof(pre));
for(i=1;i<=N;i++)
{
memset(used,0,sizeof(used));
if(find(i))
count++;
}
return count;
}
int main()
{
int i,j,t,num;
while(scanf("%d%d",&N,&M)!=EOF)
{
memset(map,0,sizeof(map));
for(i=1;i<=N;i++)
{
scanf("%d",&num);
for(j=1;j<=num;j++)
scanf("%d",&t),map[i][t]=1;
}
int ans=MMG();
printf("%d\n",ans);
}
}
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