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50题,小小的纪念下,代码留下,纯粹的二分匹配匈牙利算法模板题/*1274 Accepted 424K 16MS G++ 946B 2010-07-29 15:33:19 */ #include<stdio.h> #include<string.h> #define arr 201 int N,M,pre[arr]; bool map[arr][arr],used[arr]; bool find(int x) { int i; for(i=1;i<=M;i++) { if(!used[i]&&map[x][i]) { used[i]=1; if(pre[i]==-1||find(pre[i])) { pre[i]=x; return 1; } } } return 0; } int MMG() { int i,count=0; memset(pre,-1,sizeof(pre)); for(i=1;i<=N;i++) { memset(used,0,sizeof(used)); if(find(i)) count++; } return count; } int main() { int i,j,t,num; while(scanf("%d%d",&N,&M)!=EOF) { memset(map,0,sizeof(map)); for(i=1;i<=N;i++) { scanf("%d",&num); for(j=1;j<=num;j++) scanf("%d",&t),map[i][t]=1; } int ans=MMG(); printf("%d\n",ans); } } Followed by: Post your reply here: |
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