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Re:一次ACIn Reply To:一次AC Posted by:785815369 at 2010-07-28 09:32:04 附上代码 简单处理输入 希望给有需要的点帮助 int main() { string str; int num; char ch; cin>>str; while(1) { int sum=0; if(str=="#")break; if(str!="0") while(1) { if(str=="0")break; cin>>str>>num>>ch; if(ch=='F')sum+=num*2; else if(ch=='B')sum+=num+(int)(1.0*num/2+0.5);//四舍五入 else if(ch=='Y') { if(num<500)sum+=500; else sum+=num; } cin>>str; } cout<<sum<<endl; cin>>str; } } Followed by: Post your reply here: |
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