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哎,好简单的题啊#include <iostream> using namespace std; int pos[10000]; int main() { int N; long long sum=0; cin>>N; for(int i=1;i<=N;i++) { cin>>pos[i]; } for(int i=1;i<=N;i++) { for(int j=i+1;j<=N;j++) { sum+=2*abs(pos[j]-pos[i]); } } cout<<sum<<endl; return 0; } Followed by: Post your reply here: |
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