#include<iostream>
#include<math.h>
using namespace std;
int f(int t)
{
	if(t==1) return 1;
	else return t*t+f(t-1);
}
//求解1*1+2*2+...+t*t
int main()
{
	int x;
	while(scanf("%d",&x)&&x!=0){
		int n=sqrt(double(x*2));
		int m=n*(n+1)/2-x;
		if(m>0)printf("%d %d\n",x,f(n-1)+(n-m)*n);
		else  {
			if(m<0)printf("%d %d\n",x,f(n)-m*(n+1));
			else printf("%d %d\n",x,f(n));
		}
	}
	return 0;
}