#include<stdio.h>
int main(){
    int e,p,i,d,t=0,k;
    while(scanf("%d %d %d %d",&p,&e,&i,&d)&&(p!=-1 ||e!=-1||i!=-1||d!=-1))
    {
		t++;
		for(k=1;k<=21252;k++)
			if((k+d-p)/23*23+p-d==k && (k+d-e)/28*28+e-d==k && (k+d-i)/33*33+i-d==k) break;			
		printf("Case %d: the next triple peak occurs in %d days.\n",t,k);
	}

    return 0;
}

• Re:我来贴一个一次AC的 超级简短 的代码 (14) sndnyangd 2010-08-02 22:34:17