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用字符串做,附代码#include <iostream> using namespace std; int main() { int i,sum,b,n; char a[2000]; while(1) { scanf("%s",a); if(strcmp(a,"0")==0) break; n=strlen(a); sum=0; for(i=0;i<n;i++) sum+=a[i]-'0'; b=sum%9; if(b==0) b=9; cout<<b<<endl; } return 0; } Followed by: Post your reply here: |
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