class Reader{
		byte[] b;
		int i;
		Reader(int length){
			b = new byte[length];
			i = 0;
		}//此题length可设为1100000
		public int lineLength(){
			while(b[i]!=13&&b[i]!=10)i++;
			return i;
		}
		private void skip(){
			while(b[i]==13||b[i]==10||b[i]==32)i++;
		}
		public int nextInt(){
			skip();
			String s=new String();
			while(b[i]>47&&b[i]<58)s+=(char)b[i++];
			return Integer.parseInt(s);
		}
		public char nextChar(){
			skip();
			return (char)b[i++];
		}
	}

• Re:给个java的高效读取程序，此题读取量大，多次读取可能tle (111) 90820120 2010-06-27 23:45:30