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用括号贪心s和t分开来存，分别排序后用2个指针从头到尾指一下，看做多的左括号为多少就可以了。 真的好多trick， 可能s>t,记得要(++t)>>1,如果某时刻所指的s和t相同，一定先做s，然后更新后再做t。。 Followed by: Post your reply here: |
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