 |
| ||||
Home Page
F.A.Qs
Statistical Charts
Past Contests
Scheduled Contests
Award Contest
| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
Re:本原勾股数的构造法，（a,b,c）令 a = st, b=(s*s-t*t)/2, c = (s*s+t*t)/2, 其中s > t >= 1, 是没有公因数的奇数In Reply To:本原勾股数的构造法，（a,b,c）令 a = st, b=(s*s-t*t)/2, c = (s*s+t*t)/2, 其中s > t >= 1, 是没有公因数的奇数 Posted by:DarkArmed at 2009-07-23 17:09:45 这方法怎么得不到882个。。汗 Followed by: Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator
