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Re:代码在这,完全按照输入输出来做,为什么老是WRONG ANSWER,求人来看看

Posted by vic_jian at 2010-05-07 09:30:01 on Problem 1008
In Reply To:代码在这,完全按照输入输出来做,为什么老是WRONG ANSWER,求人来看看 Posted by:ydlsstar at 2010-05-04 17:31:22
> #include<iostream>
> #include<string>
> using namespace std;
> int main(){
> 
> 	string Haabmonth[19]={"pop","no","zip","zotz","tzec","xul","yoxkin","mol","chen",
> 			              "yax","zac","ceh","mac","kankin","muan","pax","koyab","cumhu","uayet"};
> 	string Tzoday[20]={"imix","ik","akbal","kan","chicchan","cimi","manik","lamat","muluk","ok",
> 			           "chuen","eb","ben","ix","mem","cib","caban","eznab","canac","ahau"};
> 
> 	int n,an;
> 	int count;
> 	int xtime;
> 	int ycount;
> 	int mcount;
> 	int dcount;
> 
> 	cin>>n;
> 	an=n;
> 	int day[20],year[5000],d,y;
> 	string month[19],m;
> 	char c;
> 
> 	for(int i=0;i<an;i++){
> 
> 
> 		cin>>d>>c>>m>>y;
> 		day[i]=d;
> 		month[i]=m;
> 		year[i]=y;
> 
>     }
> 	cout<<an<<endl;
> 	for(int j=0;j<an;j++){
> 
> 		for(int k=0;k<19;k++){
> 
>             if(Haabmonth[k]==month[j]){
> 
> 				count=k;
> 
> 				break;
> 			}
> 
> 		}
> 
> 		if(count==18){
> 
> 			xtime=340+day[j]+year[j]*365+1;
> 
> 		}
> 		else{
> 
> 			xtime=count*20+day[j]+year[j]*365+1;
> 
>         }
> 		ycount=(int)(xtime/260);
> 		mcount=(int)(xtime-260*ycount)%13;
> 		dcount=(int)(xtime%20);
> 
> 	    cout<<mcount<<" "<<Tzoday[dcount-1]<<" "<<ycount<<endl;
> 
>     }
> 	return 0;
> }

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