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Re:re n次快疯了,求牛人解答why?In Reply To:re n次快疯了,求牛人解答why? Posted by:wskwsk at 2010-04-22 18:05:34 >
> import java.math.BigInteger;
> import java.util.Scanner;
>
> public class Main {
>
> private static BigInteger sum = BigInteger.valueOf(0);
>
> private static void merge(int[] a, int s, int m, int t) {
> long[] tmp = new long[t - s + 1];
>
> int i = s, j = m, k = 0;
> while (i < m && j <= t) {
> if (a[i] <= a[j]) {
> tmp[k] = a[i];
> k++;
> i++;
> } else {
> tmp[k] = a[j];
> // sum += (j - i) - (j - m);
> sum = sum.add(BigInteger.valueOf((j - i) - (j - m)));
> j++;
> k++;
> }
> }
> while (i < m) {
> tmp[k] = a[i];
> i++;
> k++;
> }
>
> while (j <= t) {
> tmp[k] = a[j];
> j++;
> k++;
> }
>
> System.arraycopy(tmp, 0, a, s, tmp.length);
>
> tmp = null;
> }
>
> public static void mergeSort(int[] a, int s, int len) {
>
> while (len <= (a.length >> 1)) {
> int size = a.length;
> int mid = size / (len << 1);
> int c = size & (len - 1);
>
> // -------归并到只剩一个有序集合的时候结束算法-------//
> // if (mid == 0)
> // return;
>
> // ------进行一趟归并排序-------//
> for (int i = 0; i < mid; ++i) {
> s = i * len << 1;
> merge(a, s, s + len, (len << 1) + s - 1);
> }
>
> // -------将剩下的数和倒数一个有序集合归并-------//
> if (c != 0)
> merge(a, size - c - (len >> 1), size - c, size - 1);
> //
> // for (int i = 0; i < a.length; ++i) {
> // System.out.print(a[i] + " ");
> // }
> // System.out.println();
>
> // -------递归执行下一趟归并排序------//
> len <<= 1;
> }
> // mergeSort(a, 0, 2 * len);
> }
>
> public static void main(String[] args) {
>
> Scanner sc = new Scanner(System.in);
>
> while (true) {
> sum = BigInteger.valueOf(0);
> int size = sc.nextInt();
> if (size == 0)
> break;
> int[] a = new int[size];
> for (int i = 0; i < size; ++i) {
> a[i] = sc.nextInt();
> }
> mergeSort(a, 0, 1);
> System.out.println(sum);
> }
>
> }
>
> }
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