Online JudgeProblem SetAuthorsOnline ContestsUser
Web Board
Home Page
F.A.Qs
Statistical Charts
Problems
Submit Problem
Online Status
Prob.ID:
Register
Update your info
Authors ranklist
Current Contest
Past Contests
Scheduled Contests
Award Contest
User ID:
Password:
  Register

Re:怎么做?

Posted by 085690 at 2010-04-22 16:20:21 on Problem 3233
In Reply To:Re:怎么做? Posted by:yw1984 at 2007-06-03 18:11:04
> Let B=[ [A I];
>         [0 I] ]
> 
> B^(k+1) = [ [A^k   I+A+...+A^k];
>             [0          I     ] ]
太漂亮了..

Followed by:

Post your reply here:
User ID:
Password:
Title:

Content:

Home Page   Go Back  To top


All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator