举个例子，如果输入是S，
输出应该是 S -- is a regular palindrome.
你的是     2 -- is a regular palindrome.

> #include <iostream>
> #include <string.h>
> #include <stdio.h>
> using namespace std;
> 
> bool is_parlindrome(const char* src)
> {
> 	const char *end = src;
> 	while(*end)
> 		++end; // has pointed to ''
> 	--end;
> 	while(src < end)
> 	{
> 		if(*src++ != *end--)
> 			return false;
> 	}
> 	return true;
> }
> 
> bool is_mirrored(char* src)
> {
> 	char originalstr[10000];
> 
> 	strcpy(originalstr, src);
> 	
> 	int i;
> 	int len = strlen(src);
> 
> 	for(i=0; i<len; i++)
> 	{
> 		switch(src[i])
> 		{
> 		case 'A': src[i] = 'A'; break;
> 		case 'E': src[i] = '3'; break;
> 		case 'H': src[i] = 'H'; break;
> 		case 'I': src[i] = 'I'; break;
> 		case 'J': src[i] = 'L'; break;
> 		case 'L': src[i] = 'J'; break;
> 		case 'M': src[i] = 'M'; break;
> 		case 'O': src[i] = 'O'; break;
> 		case 'S': src[i] = '2'; break;
> 		case 'T': src[i] = 'T'; break;
> 		case 'U': src[i] = 'U'; break;
> 		case 'V': src[i] = 'V'; break;
> 		case 'W': src[i] = 'W'; break;
> 		case 'X': src[i] = 'X'; break;
> 		case 'Y': src[i] = 'Y'; break;
> 		case 'Z': src[i] = '5'; break;
> 		case '1': src[i] = '1'; break;
> 		case '2': src[i] = 'S'; break;
> 		case '3': src[i] = 'E'; break;
> 		case '5': src[i] = 'Z'; break;
> 		case '8': src[i] = '8'; break;
> 		default:
> 			return false;
> 		}
> 	}
> 
> 	//now compare the two strings
> 
> 	for(i=0; i<len; i++)
> 	{
> 		if(originalstr[i] != src[len - 1 - i])
> 			return false;
> 	}
> 
> 	return true;
> }
> 
> int main()
> {
> 	char test[100];
> 
> 	while(scanf("%s", test) != EOF)
> 	{
> 		if((is_parlindrome(test) == false) && (is_mirrored(test) == false))
> 		{
> 			cout<<test<<" -- is not a palindrome."<<endl;
> 			cout<<endl;
> 			continue;
> 		}
> 		if((is_parlindrome(test) == true) && (is_mirrored(test) == false))
> 		{
> 			cout<<test<<" -- is a regular palindrome."<<endl;
> 			cout<<endl;
> 			continue;
> 		}
> 		if((is_parlindrome(test) == false) && (is_mirrored(test) == true))
> 		{
> 			cout<<test<<" -- is a mirrored string."<<endl;
> 			cout<<endl;
> 			continue;
> 		}
> 		if((is_parlindrome(test) == true) && (is_mirrored(test) == true))
> 		{
> 			cout<<test<<" -- is a mirrored palindrome."<<endl;
> 			cout<<endl;
> 			continue;
> 		}
> 	}
> 
> 	return 0;
> }