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G++WA,C++ACIn Reply To:给出公式! 不需要解析几何! Posted by:810974380 at 2009-08-03 15:46:30 > > 先求出3边长,由海伦公式得出面积 > S=sqrt(p*(p-a)*(p-b)*(p-c)) p=(a+b+c)/2; > 由三角形面积公式S=1/2*a*b*sin(C) > 和正弦定理a/sin(A)=b/sin(B)=c/sin(C)=直径 > 可得直径=a*b*c/2/S; (a,b,c为三边长) > 所以周长即为直径*PI > > 完毕! > > 下面是A过的代码!不嫌麻烦的可以看看!!! > > #include<stdio.h> > #include<math.h> > #define PI 3.141592653589793 > double w(double a,double b,double c,double d) //求边长 > { double x; > x=sqrt((a-c)*(a-c)+(b-d)*(b-d)); > return x; > } > double g(double o,double p,double q) //求三角形面积:海伦公式 > { double m=(o+p+q)/2; > m=sqrt(m*(m-o)*(m-p)*(m-q)); > return m; > } > double h(double s,double u,double v,double w) //求直径 > {double y; > y=2*s/u/v; > y=w/y; > return y; > } > int main() > {double a,b,c,d,e,f,i,j,k,l; > while((scanf("%lf %lf %lf %lf %lf %lf",&a,&b,&c,&d,&e,&f))!=EOF){ > i=w(a,b,c,d); > j=w(a,b,e,f); > k=w(c,d,e,f); > l=g(i,j,k); > l=h(l,i,j,k); > printf("%.2lf\n",PI*l); > } > return 0; > } Followed by: Post your reply here: |
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