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Re:625MSIn Reply To:Re:625MS Posted by:Cunch at 2010-03-12 22:09:59 if(P[j].x==P[i].x&&P[j].y-P[i].y==1 || P[j].y==P[i].y&&P[j].x-P[i].x==1) > continue; 楼主你的这行好像是多余的吧 Followed by:
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