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其实不用排序只需要将字符串转换为整数然后用STL，再转为字符串输出就行了

Posted by Eli_love at 2010-03-11 15:29:46 on Problem 1256

for(i=0;i<len;i++)
		{
			if(s[i]>='a' && s[i]<='z')
				a[(s[i]-'a')*2+1]++;
			else a[(s[i]-'A')*2]++;
		}
		int cnt=0;
		for(i=0;i<53;i++)
		{
			while(a[i]--) b[cnt++]=i;
		}

Followed by:

Re:其实不用排序只需要将字符串转换为整数然后用STL，再转为字符串输出就行了 (212) zhi0901 2010-07-03 15:35:00
Re:其实不用排序只需要将字符串转换为整数然后用STL，再转为字符串输出就行了 (6) ajige 2012-06-04 09:06:26

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