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Re:同问,能够证明其正确性的acmer请解答下In Reply To:同问,能够证明其正确性的acmer请解答下 Posted by:lct_3 at 2010-03-09 19:47:17 最大独立数=未匹配的节点+匹配数/2 (1) (设n=匹配数/2,可以理解为去掉二分图某侧匹配好的n个节点,在另一侧对应的n个节点就没有相匹配的了) 而 未匹配的节点=顶点数-匹配数 (2) 由(1)(2)得: 最大独立数=顶点数-匹配数的一半 Followed by: Post your reply here: |
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