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wisdom + option + fortune = success

Posted by abilitytao at 2010-03-08 16:24:26 on Problem 2348 and last updated at 2010-03-08 16:33:10
首先结果不可能有二义性,即必须是某个确定的人获胜(W)。如果谁先获得选择权那么他就能决定在子结构中是先手还是后手。有的时候要选择先手,有时后手,谁先具有选择权,谁就能得到他想要的顺序(O).如果没有一个人能获得选择权,比如说大数始终不是小数的2倍或以上,那么只能看天意了(F).
so the function is:
wisdom + option + fortune = success 

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