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不用想用double可以蒙混过关了,能有15个有效数字正确就不错了In Reply To:求救!(请用纯小数测试,如:0.4321)为什么从某一位后的数字就不对了? Posted by:00 at 2005-03-31 17:39:40 > #include<iostream.h> > #include<iomanip.h> > #include<math.h> > double R; > int n,i,wide1,wide2; > void computation(double,int); > void main() > { > cin>>R>>n; > computation(R,n); > } > void computation(double a,int b) > { > double x=pow(a*10000,n); > for(i=0;;i++) > { > if(!floor(x/pow(10,i))) > break; > } > wide1=i; > for(i=1;;i++) > { > if(int(a*10000)%int(pow(10,i))) > break; > } > wide2=(5-i)*n; > cout<<"."; > for(i=0;i<4*n-wide1;i++) > cout<<"0"; > for(i=0;i<wide2-4*n+wide1;i++) > { > cout<<int(x/pow(10,wide1-i-1)); > x-=int(x/pow(10,wide1-i-1))*pow(10,wide1-i-1); > } > cout<<endl; > } Followed by: Post your reply here: |
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