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Re:这样做怎么就不行呢?:先求出所有强连通分支,再对每个点判断它所指向的每一点和它自己是否在同一SCC中,是则为sink点In Reply To:Re:这样做怎么就不行呢?:先求出所有强连通分支,再对每个点判断它所指向的每一点和它自己是否在同一SCC中,是则为sink点 Posted by:Iambitious at 2007-04-26 16:21:19 > 1 2 2 1 2 3你看看这个数据. 这组数据是合理数据吗? Followed by: Post your reply here: |
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