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Re:不好调整啊In Reply To:模拟退火算法,125msAC Posted by:bobchennan at 2010-01-20 11:27:55 > 具体算法参考《浅谈随机化思想在几何问题中的应用》。 > C++ 125ms Accept! > void solve() > { > int p=10,l=25; > double delta,epsilon=1e-2,k1,k2,n1,n2,an[11]; > delta=(double)max(x,y)/(sqrt(1.0*m)); > for (int r=1;r<=p;r++) > { > q[r][0]=double(rand()%1000+1)/1000.000*x; > q[r][1]=double(rand()%1000+1)/1000.000*y; > double max=oo; > for (int i=1;i<=m;i++) > { > double tmp=dist(q[r][0],q[r][1],hole[i].xi,hole[i].yi); > if (tmp<max) max=tmp; > } > an[r]=max; > } > while (delta>epsilon) > { > for (int r=1;r<=p;r++) > { > for (int i=1;i<=l;i++) > { > k1=double(rand()%1000+1)/1000.000*delta; > k2=sqrt(delta*delta-k1*k1); > if (rand()%2==1) k1*=-1; > if (rand()%2==1) k2*=-1; > n1=q[r][0]+k1; > n2=q[r][1]+k2; > if (n1<=x&&n2<=y&&n1>=0&&n2>=0) > { > double max1=oo; > for (int j=1;j<=m;j++) > { > double tmp=dist(n1,n2,hole[j].xi,hole[j].yi); > if (tmp<max1) max1=tmp; > } > if (max1>an[r]) > q[r][0]=n1,q[r][1]=n2,an[r]=max1; > } > else > continue; > } > } > delta*=0.8; > } > double max=-oo; > int s1=0; > for (int r=1;r<=p;r++) > if (an[r]>max) > max=an[r],s1=r; > ans.xi=q[s1][0]; > ans.yi=q[s1][1]; > } Followed by: Post your reply here: |
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