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ce一次后AC了！没有d<0和y<0的情况利用贪心，先按x从左到右排序。求出每个点对应的雷达可以再的区间，然后判断区间之间是否有重复，有的话更新区间，没有的话让cnt++，表示要新增一个雷达，走完n次后，cnt就是所求结果 Followed by: Post your reply here: |
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