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Re:不会吧 好不容易出来了 又超时!!!!!!!!!!1In Reply To:不会吧 好不容易出来了 又超时!!!!!!!!!!1 Posted by:vince4053040 at 2009-12-23 15:25:22 #include<iostream>
#include<cmath>
using namespace std;
int main()
{
int n,m,k,max,pp,N;
int step,sum;
int i,j,x_1,x_2,y_1,y_2;
int a[56][56];
cin>>N;
while(N--)
{
cin>>n>>m>>k;
max=0;
step=k-2;
sum=0;
for(i=0;i<n;i++)
{
for(j=0;j<m;j++)
{
scanf("%d",&a[i][j]);
if(a[i][j]>max)
{
max=a[i][j];
x_1=i;
y_1=j;
}
}
}
sum+=a[x_1][y_1];
//cout<<x_1;
//cout<<a[x_1][y_1];
a[x_1][y_1]=0;
step -= 2 * (x_1 + 1); //天呐 X Y都分不清
//cout<<step;
x_2 = x_1; //为下面开始step值不变作保证
//cout<<x_2;
if(step<0)
{
cout<<0<<endl;
}
else{
max=0;
//cout<<step;
//cout<<x_2;
//cout<<x_1<<" "<<y_1;
while(step>0)
{
max=0;
step += x_2 + 1;// + 1; //把多减的部分加回来
//cout<<step<<" ";
for(i=0;i<n;i++)
{
for(j=0;j<m;j++)
{
if(a[i][j]>max)
{
max=a[i][j];
x_2=i;
y_2=j;
//cout<<max<<" ";
}
}
}
sum+=max;
//cout<<sum<<" ";
//cout<<a[x_2][y_2]<<" ";
pp=a[x_2][y_2]; //最后减去用
a[x_2][y_2]=0;
step -= (abs(x_2 - x_1) + abs(y_2 - y_1) + x_2 + 1);// + 1;
x_1 = x_2;
y_1 = y_2;
}
cout<<sum - pp<<endl;
}
}
return 0;
}
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