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简单Dp,主要是要搞清楚时间的转换Time[i],表示第i辆车过河 并且船回来(注意)的时间;
Trip[i],表示第i辆车过完河 ,船的来回次数;
temp = max(Time[j],T[i]) + 2*t;/*why??*/
if (temp >= Time[i])
{
if(temp == Time[i]) Trip[i]...
else Trip[i]...
Time[i] = temp;
}
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