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多重背包思路可以过么？共6个物品，价值和重量相等，都等于1，或者2，或者3...6 sum = sum + i*p[i] 然后求容量为sum/2的背包的解，如果f[sum/2] = sum/2; 就可以divide 这个思路有错么？ Followed by:
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