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2个解法1.暴搜，精度要求较低，可以去三点的中点，然后写一个估值函数，之后像求费马点那样迭代求更好的估值。 2.两两圆的计算，可以证明结果只能是直线或者圆，求交点即可，but，我拿标程都交不过 而且非常难写 Followed by: Post your reply here: |
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