> #include <iostream.h>//1547
> void main()
> {
> 	int a[9],b[9],c[9],e[9],f,g;
> 	int time=0,p;
> 	char d[9][9];
> 	while(time!=-1)
> 	{
> 		cin>>time;
> 		for(int i=0;i<time;i++)
> 		{
> 			cin>>a[i]>>b[i]>>c[i]>>d[i];
> 			e[i]=(a[i]+b[i]+c[i])/3;
> 		}
> 		p=0;
> 		for(i=0;i<time;i++)
> 			p+=e[i];
> 		p/=time;
> 		for(i=0;i<time;i++)
> 		{
> 			if(e[i]>p)
> 				f=i;
> 			if(e[i]<p)
> 				g=i;
> 		}
> 	cout<<d[f]<<" took clay from "<<d[g]<<"."<<endl;
> 	}
> }
> 

• Re:什么是无法运行？ (13) 1987 2005-03-25 18:27:00
  • 郁闷 (17) 1987 2005-03-25 18:30:04
    • 郁闷 (864) 1987 2005-03-25 18:31:16
      • Re:郁闷 (868) 1987 2005-03-25 18:31:22
        • 仔细检查:) (0) sothink 2005-03-25 19:14:49