#include <iostream.h>//1547
void main()
{
	int a[9],b[9],c[9],e[9],f,g;
	int time=0,p;
	char d[9][9];
	while(time!=-1)
	{
		cin>>time;
		for(int i=0;i<time;i++)
		{
			cin>>a[i]>>b[i]>>c[i]>>d[i];
			e[i]=(a[i]+b[i]+c[i])/3;
		}
		p=0;
		for(i=0;i<time;i++)
			p+=e[i];
		p/=time;
		for(i=0;i<time;i++)
		{
			if(e[i]>p)
				f=i;
			if(e[i]<p)
				g=i;
		}
	cout<<d[f]<<" took clay from "<<d[g]<<"."<<endl;
	}
}

• 什么是无法运行？ (500) hawk 2005-03-25 18:00:44
  • Re:什么是无法运行？ (13) 1987 2005-03-25 18:27:00
    • 郁闷 (17) 1987 2005-03-25 18:30:04
      • 郁闷 (864) 1987 2005-03-25 18:31:16
        • Re:郁闷 (868) 1987 2005-03-25 18:31:22
          • 仔细检查:) (0) sothink 2005-03-25 19:14:49