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Re:秀代码的又来了In Reply To:秀代码的又来了 Posted by:zjut020 at 2008-11-22 22:23:05 这个题目DP 就可以时间复杂在n
#include<stdio.h>
#include<stdlib.h>
int abs(int x)
{
if(x<0)
return -x;
return x;
}
int cmp(void const *a,void const *b)
{
return (*(int*)a)>(*(int*)b)?1:-1;
}
int main()
{
__int64 sum,dp;
int s[10005],t,k,i,c;
while(scanf("%d",&t)!=EOF)
{
sum=dp=c=0;
for(i=0;i<t;i++)
{
scanf("%I64d",&s[i]);
}
qsort(s,t,sizeof(s[0]),cmp);
for(i=0;i<t;i++)
{
sum+=(__int64)s[i]*i-(__int64)dp;
dp+=s[i];
// printf("dp=%I64d\n",(__int64)s[i]*i);
}
printf("%I64d\n",sum*2);
}
return 0;
}
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