Online Judge | Problem Set | Authors | Online Contests | User | ||||||
---|---|---|---|---|---|---|---|---|---|---|
Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest |
谁能帮帮忙,看一下错在那?测试数据都行,谢谢#include<iostream.h> #include<stdlib.h> void main() { int in[4],j,count=0; do{ j=0; for(long int i=0;i<4;i++) { cin>>in[i]; if(in[i]==-1) j++; } if(j==4)exit(0); count++; long int res,temp1,temp2,temp3,temp4; for(i=1;;i++) { temp1=(10*i+in[2]-in[0])%23; temp2=(5*i+in[2]-in[1])%28; temp3=i+(10*i+in[2]-in[0])/23; temp4=i+(5*i+in[2]-in[1])/28; res=i*33+in[2]-in[3]; if(temp1==0&&temp2==0&&res>0&&temp3>0&&temp4>0) { break; } } cout<<"Case "<<count<<": the next triple peak occurs in " <<res<<" days."<<endl; }while(1==1); } Followed by: Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator